How can I pass arguments to a batch file?

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You can pass arguments to a batch file in Windows by including them after the batch file's name when you execute it. These arguments can be accessed within the batch script using special variables like %1, %2, and so on. Here's how you can do it with an example:

Example Batch Script (myscript.bat):

batch
@echo off
echo My Batch Script

REM Accessing the first argument
echo First argument: %1

REM Accessing the second argument
echo Second argument: %2

REM Accessing all arguments
echo All arguments: %*

REM Count of arguments
echo Number of arguments: %#

REM Loop through all arguments
echo Loop through all arguments:
for %%a in (%*) do (
    echo %%a
)

pause

In this script:

  • %1 refers to the first argument.
  • %2 refers to the second argument.
  • %* refers to all arguments.
  • # is used to count the number of arguments.
  • The for loop is used to iterate through all the arguments.

Executing the Batch Script with Arguments:

Suppose you have the batch script saved as "myscript.bat," and you want to pass arguments to it. You can do so when running the script from the command prompt:

batch
myscript.bat arg1 arg2 arg3

In this example, we're passing three arguments, "arg1," "arg2," and "arg3," to the batch script.

Output:

When you run the script with these arguments, you'll see the following output:

sql
My Batch Script
First argument: arg1
Second argument: arg2
All arguments: arg1 arg2 arg3
Number of arguments: 3
Loop through all arguments:
arg1
arg2
arg3
Press any key to continue . . .

The batch script processes the arguments as shown in the script example, allowing you to pass data to the script from the command line. You can access and use these arguments within your batch script as needed for your specific task.

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